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Free Ohm's Law Calculator

Enter any two of voltage, current, resistance, or power — get the other two instantly, including the full power formulas (P = VI, I²R, V²/R).

Enter any two values to solve for the other two.

Voltage
volts (V)
Current
amps (A)
Resistance
ohms (Ω)
Power
watts (W)

Ohm's law and the power wheel

Ohm's law ties together the three fundamentals of any circuit: voltage (V), current (I), and resistance (R) — V = I × R. Add power (P) and you have the four-quantity "Ohm's law wheel," where knowing any two lets you solve the rest.

The twelve relationships: V = IR = P/I = √(PR). I = V/R = P/V = √(P/R). R = V/I = V²/P = P/I². P = VI = I²R = V²/R. This calculator picks the right pair automatically based on which two boxes you fill.

On real installations this is the math behind sizing a breaker for a known load, checking conductor heating (I²R losses), and sanity-checking a reading in the field. For loads on a project, Field PM tracks the equipment and circuits alongside your project documentation — note that motors and other reactive AC loads also need power factor for true watts.

FAQ

What is Ohm's law?+

Ohm's law states that voltage equals current times resistance: V = I × R. Rearranged, current I = V ÷ R and resistance R = V ÷ I. Add power and you get the full "Ohm's law wheel": P = V × I, P = I² × R, and P = V² ÷ R.

How do I find power from voltage and current?+

Power in watts equals voltage times current: P = V × I. A 120 V circuit drawing 10 A is using 1,200 watts. If you know current and resistance instead, P = I² × R; with voltage and resistance, P = V² ÷ R.

How do I calculate amps from watts and volts?+

Current equals power divided by voltage: I = P ÷ V. A 1,500 W heater on 120 V draws 12.5 A. This is the calculation behind sizing breakers and conductors for a known load.

Does Ohm's law work for AC circuits?+

For purely resistive AC loads (heaters, incandescent lighting), yes — use RMS values. For motors and other reactive loads, true power also depends on the power factor (P = V × I × PF), so the simple wheel gives apparent power (VA), not real watts.

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